mensuration area volumes Model Questions & Answers, Practice Test for ibps so prelims 2023

Answer: (a)

Given

AB = 4.8 cm

BC = 7.2 and BX = 2 cm

∴ AX = AB – BX = 4.8 – 2 = 2.8 cm

ΔAXY ≈ ΔABC

∴ ${XY}/{BC} = {AX}/{AB} ⇒ XY = {AX}/{AB} . BC = {2.8}/{4.8} × 7.2$

∴ XY = 4.2 cm

Answer: (d)

Given that AB = BC = CD, also since AB is the radius then AB = AC = AD = radius, so we have that: AB = BC = CD = AC = AD, so basically we have two equilateral triangles ABC and ACD with common base of AC (ABC and ACD are mirror images of each other). Line segment BD cuts the angle ABC in half and since all angles in equilateral triangle equal to 60 degrees then x = 60/2 = 30 degrees.

Answer: (a)

From figure, arc length PQ = ${2πr}/{360°}$ × θ

∴ 120 = ${2 × 3.14 × r × 25°}/{360°}$

⇒ r = ${120 × 360}/{2 × 3.14 × 25} = {43200}/{157}$ = 275.15 m

r = 275 m (approx)

Answer: (c)

Let sides of cuboid be a, b, c

x = $a^2$

y = $b^2$

z = $c^2$

volume of cuboid

V = a. b. c

$V^2 = a^2 b^2 c^2$

$V^2$ = x . y. z

So, option (c) is correct

Answer: (b)

Let inner radius of the pipe be r.

Then, 440 = ${22}/7 × r^2$ × 7 × 10

or $ r^2 = {440}/{22 × 10}$ = 2

or r = $√2$m